.3x^2=25

Solution for .3x^2=25 equation:

.3x^2=25

We move all terms to the left:

.3x^2-(25)=0

a = .3; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·.3·(-25)
Δ = 30
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{30}}{2*.3}=\frac{0-\sqrt{30}}{0.6}
=-\frac{\sqrt{}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{30}}{2*.3}=\frac{0+\sqrt{30}}{0.6}
=\frac{\sqrt{}}{0.6}
$